35x^2+13x-198=0

Solution for 35x^2+13x-198=0 equation:

35x^2+13x-198=0

a = 35; b = 13; c = -198;
Δ = b2-4ac
Δ = 132-4·35·(-198)
Δ = 27889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{27889}=167$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-167}{2*35}=\frac{-180}{70}
=-2+4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+167}{2*35}=\frac{154}{70}
=2+1/5
$